Volume and surface area

Advanced Math 6 · Unit 12 · volume-surface-nets · Teacher edition

volume-surface-nets
Name ______________________________Date ______________
  1. 1.

    A box measures 33 cm by 44 cm by 55 cm. What is its surface area in cm²?

    Answer: ______________

  2. 2.

    Find the volume of a rectangular prism with edges 2122\dfrac{1}{2} cm, 1131\dfrac{1}{3} cm, and 33 cm, in cm³.

    Answer: ______________

  3. 3.

    A cube has a surface area of 150150 cm². What is the length of one edge, in cm?

    Answer: ______________

  4. 4.

    A box measures 2×3×62 \times 3 \times 6. When its net is drawn, which of these is not the area of one of the faces?

    1. (A)

      66

    2. (B)

      99

    3. (C)

      1212

    4. (D)

      1818

  5. 5.

    A rectangular tank has volume 7127\dfrac{1}{2} cubic feet. Its base is 2122\dfrac{1}{2} ft by 22 ft. How tall is it, in feet?

    Answer: ______________

Answer key — Volume and surface area

  1. 1.
    94volume-surface-nets-01

    S=2(12+15+20)=2×47=94S = 2(12 + 15 + 20) = 2 \times 47 = \mathbf{94} cm². (Using 6×3×4=726 \times 3 \times 4 = 72 treats it as a cube.)

  2. 2.
    10volume-surface-nets-02

    52×43×3=52×4=10\frac{5}{2} \times \frac{4}{3} \times 3 = \frac{5}{2} \times 4 = \mathbf{10} cm³.

  3. 3.
    5volume-surface-nets-03

    One face: 150÷6=25150 \div 6 = 25 cm², so the edge is 25=5\sqrt{25} = \mathbf{5} cm.

  4. 4.
    (B)

    99

    volume-surface-nets-04

    Faces: 66, 1212, 1818 (each appearing twice). 9\mathbf{9} is not a face area — it would need a 3×33 \times 3 face, and there is no pair of equal edges.

  5. 5.
    1.5volume-surface-nets-05

    Base area =52×2=5= \frac{5}{2} \times 2 = 5. Height =152÷5=1510=112= \frac{15}{2} \div 5 = \frac{15}{10} = \mathbf{1\tfrac{1}{2}} ft. Check: 5×1.5=7.55 \times 1.5 = 7.5 ✓.