Whole numbers to one billion

Advanced Math 5 · Unit 1 · place-value-billion · Teacher edition

place-value-billion
Name ______________________________Date ______________
  1. 1.

    Round 438,516,207438{,}516{,}207 to the nearest million.

    Answer: ______________

  2. 2.

    A roll of ribbon is 3.453.45 m long. A factory has 10310^3 rolls. What is the total length of ribbon, in metres?

    Answer: ______________

  3. 3.

    One bead has a mass of 4.24.2 grams. What is the mass of 100100 beads, in grams?

    1. (A)

      4.2004.200

    2. (B)

      4242

    3. (C)

      420420

    4. (D)

      4,2004{,}200

    5. (E)

      0.0420.042

Answer key — Whole numbers to one billion

  1. 1.
    439000000place-value-billion-01

    438,516,207438{,}516{,}207 is between 438,000,000438{,}000{,}000 and 439,000,000439{,}000{,}000. The hundred-thousands digit is 55, so round up: 439,000,000\mathbf{439{,}000{,}000}.

  2. 2.
    3450place-value-billion-02

    103=1,00010^3 = 1{,}000, and 3.45×1,000=3,4503.45 \times 1{,}000 = 3{,}450: the point moves three places right and a zero fills the empty place. Total length 3,450\mathbf{3{,}450} m. (3.450003.45000 is the same number as 3.453.45; writing zeros after the point changes nothing.)

  3. 3.
    (C)

    420420

    place-value-billion-03

    4.2×100=4204.2 \times 100 = 420 grams. Sense check: 100100 beads of about 44 g each is about 400400 g. Answer 420\mathbf{420}. (4.2004.200 is still 4.24.2 — zeros after the point add nothing; 4242 moves the point only one place; 4,2004{,}200 moves it three; 0.0420.042 divides instead.)