Simple equations in one variable

Advanced Math 7 · Unit 5 · linear-equations-7 · Teacher edition

linear-equations-7
Name ______________________________Date ______________
  1. 1.

    Solve 5x7=3x+95x - 7 = 3x + 9.

    Answer: ______________

  2. 2.

    Solve x+53=x12\dfrac{x + 5}{3} = \dfrac{x - 1}{2}.

    Answer: ______________

  3. 3.

    Maya is three times as old as Ben. In 88 years she will be twice as old as Ben will be then. How old is Ben now?

    Answer: ______________

  4. 4.

    Solve x3+2=x4+5\dfrac{x}{3} + 2 = \dfrac{x}{4} + 5.

    1. (A)

      33

    2. (B)

      1212

    3. (C)

      3636

    4. (D)

      8484

  5. 5.

    The length of a rectangle is 33 cm more than twice its width. Its perimeter is 4848 cm. What is its area, in cm²?

    1. (A)

      6363

    2. (B)

      105105

    3. (C)

      119119

    4. (D)

      144144

    5. (E)

      238238

Answer key — Simple equations in one variable

  1. 1.
    8linear-equations-7-01

    5x7=3x+92x=16x=85x - 7 = 3x + 9 \Rightarrow 2x = 16 \Rightarrow x = \mathbf{8}. Check: 407=3340 - 7 = 33 and 24+9=3324 + 9 = 33. ✓

  2. 2.
    13linear-equations-7-02

    6×x+53=2(x+5)6 \times \frac{x + 5}{3} = 2(x + 5) and 6×x12=3(x1)6 \times \frac{x - 1}{2} = 3(x - 1), so 2x+10=3x32x + 10 = 3x - 3 and x=13x = \mathbf{13}. Check: 183=6=122\frac{18}{3} = 6 = \frac{12}{2}. ✓

  3. 3.
    8linear-equations-7-03

    3b+8=2b+16b=83b + 8 = 2b + 16 \Rightarrow b = \mathbf{8}. Ben is 88 and Maya is 2424; in 88 years they are 1616 and 3232, and 32=2×1632 = 2 \times 16. ✓

  4. 4.
    (C)

    3636

    linear-equations-7-04

    12(x3+2)=4x+2412\left(\frac{x}{3} + 2\right) = 4x + 24 and 12(x4+5)=3x+6012\left(\frac{x}{4} + 5\right) = 3x + 60, so x=36x = \mathbf{36}. Check: 12+2=1412 + 2 = 14 and 9+5=149 + 5 = 14. ✓ (33 comes from 4x+2=3x+54x + 2 = 3x + 5, forgetting to multiply the constants; 8484 adds 60+2460 + 24 instead of subtracting.)

  5. 5.
    (C)

    119119

    linear-equations-7-05

    2(3w+3)=483w+3=24w=72(3w + 3) = 48 \Rightarrow 3w + 3 = 24 \Rightarrow w = 7. Length =2(7)+3=17= 2(7) + 3 = 17. Area =7×17=119= 7 \times 17 = \mathbf{119} cm². (238=14×17238 = 14 \times 17 uses 2w2w as the width; 144=122144 = 12^2 treats the rectangle as a square with perimeter 4848.)