Graphing functions

High School Math 1 · Unit 11 · function-features · Teacher edition

function-features
Name ______________________________Date ______________
  1. 1.

    A piecewise function is defined by

    f(x)={x+3if x<02xif x0f(x) = \begin{cases} x + 3 & \text{if } x < 0 \\ 2x & \text{if } x \ge 0 \end{cases}

    Find f(2)f(-2).

    Answer: ______________

  2. 2.

    Let f(x)=x22xf(x) = x^{2} - 2x. Find the average rate of change of ff from x=1x = 1 to x=4x = 4.

    Answer: ______________

  3. 3.

    A graph starts at (4,2)(-4, 2), falls to a low point at (1,3)(-1, -3), rises to a high point at (2,5)(2, 5), then falls to its end at (5,0)(5, 0). On which interval is the function increasing?

    1. (A)

      (1,2)(-1, 2)

    2. (B)

      (4,1)(-4, -1)

    3. (C)

      (2,5)(2, 5)

    4. (D)

      (3,5)(-3, 5)

  4. 4.

    The table gives the height h(t)h(t), in metres, of a drone tt seconds after launch.

    tt002255
    h(t)h(t)121220204444

    What is the average rate of change of hh from t=2t = 2 to t=5t = 5, in metres per second?

    1. (A)

      2424

    2. (B)

      88

    3. (C)

      323\dfrac{32}{3}

    4. (D)

      6.46.4

  5. 5.

    What is the maximum value of the function f(x)=x2+6x5f(x) = -x^{2} + 6x - 5?

    Answer: ______________

Answer key — Graphing functions

  1. 1.
    1function-features-01

    2<0-2 < 0, so f(2)=2+3=1f(-2) = -2 + 3 = \mathbf{1}. (Using 2x2x would give 4-4, but that rule is only for x0x \ge 0.)

  2. 2.
    3function-features-02

    f(4)f(1)41=8(1)3=93=3\dfrac{f(4) - f(1)}{4 - 1} = \dfrac{8 - (-1)}{3} = \dfrac{9}{3} = \mathbf{3}.

  3. 3.
    (A)

    (1,2)(-1, 2)

    function-features-03

    The graph rises between the low point and the high point, so ff is increasing on (1,2)\mathbf{(-1, 2)}. ((3,5)(-3, 5) lists the yy-values of those two points, not an xx-interval; on (4,1)(-4, -1) and (2,5)(2, 5) the graph is falling.)

  4. 4.
    (B)

    88

    function-features-04

    h(5)h(2)52=44203=8\dfrac{h(5) - h(2)}{5 - 2} = \dfrac{44 - 20}{3} = \mathbf{8} m/s. (2424 is h(5)h(2)h(5) - h(2) without dividing by the time; 323\frac{32}{3} uses the height change from t=0t = 0; 6.46.4 is 325\frac{32}{5}, the rate over the whole table.)

  5. 5.
    4function-features-05

    Vertex at x=3x = 3; f(3)=9+185=4f(3) = -9 + 18 - 5 = \mathbf{4}. The maximum value is 44, reached at x=3x = 3. (Reporting 33 answers “where,” not “what.”)