Perimeters and areas of plane figures (circles)

Advanced Math 7 · Unit 12 · circles-arcs-sectors · Teacher edition

circles-arcs-sectors
Name ______________________________Date ______________
  1. 1.

    A circle has diameter 1414 cm. Its circumference is kπk\pi cm. Enter kk.

    Answer: ______________

  2. 2.

    A sector of a circle has radius 99 cm and central angle 120120^\circ. Its area is kπk\pi cm². Enter kk.

    Answer: ______________

  3. 3.

    A square has side 88 cm. A quarter circle with its center at one corner of the square and radius 88 cm is cut away. Using π3.14\pi \approx 3.14, what is the area of the remaining piece, in cm²?

    Answer: ______________

  4. 4.

    A sector has radius 66 cm and central angle 6060^\circ. What is its area?

    1. (A)

      32π\dfrac{3}{2}\pi cm²

    2. (B)

      2π2\pi cm²

    3. (C)

      6π6\pi cm²

    4. (D)

      36π36\pi cm²

  5. 5.

    A circle is inscribed in a square of side 1212, touching all four sides. The total area of the four corner regions — inside the square but outside the circle — can be written as abπa - b\pi for positive integers aa and bb. What is a+ba + b?

    1. (A)

      108108

    2. (B)

      144144

    3. (C)

      156156

    4. (D)

      180180

    5. (E)

      288288

Answer key — Perimeters and areas of plane figures (circles)

  1. 1.
    14circles-arcs-sectors-01

    C=πd=14πC = \pi d = 14\pi, so k=14k = \mathbf{14}. (2828 treats 1414 as the radius.)

  2. 2.
    27circles-arcs-sectors-02

    A=120360×π×81=27πA = \frac{120}{360} \times \pi \times 81 = 27\pi, so k=27k = \mathbf{27}. (The arc length would be 13×18π=6π\frac{1}{3} \times 18\pi = 6\pi — a different question.)

  3. 3.
    13.76circles-arcs-sectors-03

    Quarter circle =14π(82)=16π50.24= \frac{1}{4}\pi(8^2) = 16\pi \approx 50.24. Remaining =6450.24=13.76= 64 - 50.24 = \mathbf{13.76} cm².

  4. 4.
    (C)

    6π6\pi cm²

    circles-arcs-sectors-04

    A=16×36π=6πA = \frac{1}{6} \times 36\pi = \mathbf{6\pi} cm². (2π2\pi is 16×2πr\frac{1}{6} \times 2\pi r — the arc length, not the area; 32π\frac{3}{2}\pi uses r=3r = 3, half the radius; 36π36\pi is the whole circle.)

  5. 5.
    (D)

    180180

    circles-arcs-sectors-05

    r=6r = 6, so the corners have area 14436π144 - 36\pi and a+b=144+36=180a + b = 144 + 36 = \mathbf{180}. (288288 uses r=12r = 12, the diameter; 156156 uses 12π12\pi for the circle; 144144 forgets the circle.)