Algebraic expressions

Advanced Math 6 · Unit 8 · algebraic-expressions-6 · Teacher edition

algebraic-expressions-6
Name ______________________________Date ______________
  1. 1.

    Evaluate 3x+23x + 2 when x=4x = 4.

    Answer: ______________

  2. 2.

    Which expression is equivalent to 3(2x+4)+x3(2x + 4) + x?

    1. (A)

      6x+46x + 4

    2. (B)

      7x+127x + 12

    3. (C)

      6x+126x + 12

    4. (D)

      7x2+127x^2 + 12

  3. 3.

    Simplify 3(2x+4)+x3(2x + 4) + x, then evaluate it at x=12x = \dfrac{1}{2}.

    Answer: ______________

  4. 4.

    Simplify 5y+32y+75y + 3 - 2y + 7.

    1. (A)

      7y+107y + 10

    2. (B)

      13y13y

    3. (C)

      3y+103y + 10

    4. (D)

      3y2+103y^2 + 10

  5. 5.

    Factor 12x+1812x + 18 by taking out the greatest common factor.

    1. (A)

      2(6x+9)2(6x + 9)

    2. (B)

      3(4x+6)3(4x + 6)

    3. (C)

      6(2x+3)6(2x + 3)

    4. (D)

      6(2x+18)6(2x + 18)

Answer key — Algebraic expressions

  1. 1.
    14algebraic-expressions-6-01

    3(4)+2=12+2=143(4) + 2 = 12 + 2 = \mathbf{14}. (Writing 34+234 + 2 is the classic slip.)

  2. 2.
    (B)

    7x+127x + 12

    algebraic-expressions-6-02

    3(2x+4)+x=6x+12+x=7x+123(2x+4) + x = 6x + 12 + x = \mathbf{7x + 12}. (6x+46x + 4 forgets to distribute to the 44; 6x+126x + 12 forgets the extra xx; 7x27x^2 multiplies xx-terms instead of adding them.)

  3. 3.
    15.5algebraic-expressions-6-03

    7x+127x + 12 at x=12x = \frac{1}{2}: 3.5+12=15.53.5 + 12 = \mathbf{15.5}. Check without simplifying: 3(1+4)+0.5=15+0.5=15.53(1 + 4) + 0.5 = 15 + 0.5 = 15.5. ✓

  4. 4.
    (C)

    3y+103y + 10

    algebraic-expressions-6-04

    5y2y=3y5y - 2y = 3y and 3+7=103 + 7 = 10, so 3y+10\mathbf{3y + 10}. (13y13y mixes numbers into the yy-term; 7y7y adds instead of subtracting.)

  5. 5.
    (C)

    6(2x+3)6(2x + 3)

    algebraic-expressions-6-05

    12x+18=6(2x+3)12x + 18 = \mathbf{6(2x + 3)}. Check by distributing: 62x+63=12x+186 \cdot 2x + 6 \cdot 3 = 12x + 18 ✓. 2(6x+9)2(6x+9) and 3(4x+6)3(4x+6) are true but not fully factored; 6(2x+18)6(2x + 18) expands to 12x+10812x + 108.