Introduction to algebra

Advanced Math 7 · Unit 3 · algebra-foundations-7 · Teacher edition

algebra-foundations-7
Name ______________________________Date ______________
  1. 1.

    In the expression 5x23x+75x^2 - 3x + 7, what is the coefficient of xx?

    Answer: ______________

  2. 2.

    Write an expression for “seven less than twice a number nn.”

    Answer: ______________

  3. 3.

    Here are four algebraic sentences.

    (i) 3x+2=113x + 2 = 11 (ii) A=πr2A = \pi r^2 (iii) 2(x+3)=2x+62(x + 3) = 2x + 6 (iv) 4x74x - 7

    Which one is an identity — true for every value of xx?

    1. (A)

      (i)

    2. (B)

      (ii)

    3. (C)

      (iii)

    4. (D)

      (iv)

  4. 4.

    Which of these is an expression (not an equation)?

    1. (A)

      x=5x = 5

    2. (B)

      12x4\dfrac{1}{2}x - 4

    3. (C)

      2x+3=92x + 3 = 9

    4. (D)

      y=3xy = 3x

  5. 5.

    What is the value of x32x2+3x4x^3 - 2x^2 + 3x - 4 when x=2x = -2?

    Answer: ______________

Answer key — Introduction to algebra

  1. 1.
    -3algebra-foundations-7-01

    The xx-term is 3x-3x, so the coefficient is 3\mathbf{-3}. (55 is the coefficient of x2x^2; 77 is the constant term.)

  2. 2.
    2n72n-7algebra-foundations-7-02

    Twice nn is 2n2n; seven less than that is 2n7\mathbf{2n - 7}. (72n7 - 2n reads the words in order and gets the subtraction backwards.)

  3. 3.
    (C)

    (iii)

    algebra-foundations-7-03

    (iii): 2(x+3)=2x+62(x + 3) = 2x + 6 is true for every xx (expand the left side), so it is an identity. (i) is true only at x=3x = 3 — an equation to solve. (ii) is a formula. (iv) is an expression. Answer: (iii).

  4. 4.
    (B)

    12x4\dfrac{1}{2}x - 4

    algebra-foundations-7-04

    12x4\mathbf{\tfrac{1}{2}x - 4} has no equals sign, so it is an expression. x=5x = 5 is an equation (its solution is 55), and so are 2x+3=92x + 3 = 9 and y=3xy = 3x.

  5. 5.
    -26algebra-foundations-7-05

    (2)32(2)2+3(2)4=8864=26(-2)^3 - 2(-2)^2 + 3(-2) - 4 = -8 - 8 - 6 - 4 = \mathbf{-26}. (Reading 2x2-2x^2 as (2x)2=16(-2x)^2 = 16 gives 8+1664=2-8 + 16 - 6 - 4 = -2, the classic sign error.)